Bet Sizing With Skewed Returns
An Amendment to the Kelly Criterion
The continuous form of Kelly betting traditionally relies on the first two moments of the return distribution. This simplification does not consider the effects of higher-order moments like skewness and kurtosis. However, real-world stock returns often exhibit negative skew (a tendency for large losses) and positive excess kurtosis (a higher frequency of extreme returns), which significantly impact the distribution of outcomes. These characteristics imply that the standard Kelly formula underestimates the risks associated with large drawdowns and overstates the likelihood of achieving the expected growth rate. To more accurately optimize the growth rate, the formula should incorporate adjustments for skewness and kurtosis. By doing so, the strategy can better account for the asymmetry and fat tails present in actual return distributions, leading to a more robust and realistic measure of optimal leverage.
Review: Kelly Criterion
The Kelly Criterion is an approach to determine the optimal allocation of capital to maximize long-term growth of wealth. The core idea is to invest a proportion of capital that maximizes the logarithm of wealth, ensuring the highest expected geometric / compounded rate of growth over time (i.e. leads to higher wealth than any other strategy in the long run with probability 1) while avoiding the risk of ruin.
For a discrete outcome scenario, such as a gamble with known probabilities of winning and losing, the optimal betting fraction is
Where p is the probability of win, b is the factor by which wealth increases in the winning case, q is the probability of loss, and a is the factor by which wealth decreases in the losing case.
Continuous Kelly
For the continuous case of normally distributed return with known mean and variance, the optimal leverage factor to optimize the compounded rate of growth is
We now show a proof sketch and in the process also determine how we can incorporate skewness and kurtosis into our estimate of the optimal leverage. Let our wealth at time n be represented as a product of bet fraction f and return on bet Xi
We take log-returns i.e. compounded rate of growth
The expectation of the above can be given by
where g(x) is the distribution of returns x. The optimal bet size f is clearly independent of n, so we can optimize the expectation with respect to f by taking the partial derivative with respect to f and setting the resulting term to 0. Before doing that, we can consider the Taylor approximation
which transforms the target of optimization into
defining moments of x under g
we can reinterpret the target of optimization as
differentiating with respect to f, we require
which is a cubic in f which is solvable analytically. Note that for the case where we ignore skew and kurtosis (i.e. only consider the constant and linear term), the optimal allocation leverage f is given by
which is what was claimed previously.
The Correction for Skewness
In the case of only skewness and no kurtosis
Per the quadratic formula, we have
Real solutions exist if and only if
This is clearly “wrong” (an optimal allocation exists regardless of the relationship between moments) and is a consequence of our non-rigorous use of Taylor approximations. For now, we assume that the discriminant is indeed nonsingular.
It remains the case that we don’t know which root is the correct one. In addition, note that skewness being zero leads to a singularity; but also recall that we already have an expression for when skewness is ignored completely! This means that we can address these issues by considering the limit as skewness approaches zero. This helps us consider the smooth transition between the case of ignoring skewness where we have a valid formula and the case of not ignoring skewness i.e. it maximizes the value of the discriminant and makes it obvious whether we should take the plus root or the minus root. Regarding the components of the discriminant we now have
This allows us to use a Taylor approximation on the square root of the discriminant. In particular, recall that the Binomial Series for the square root of 1 - x is
Letting x = b / a we note that
This is valid only if a >> b which is true if we let a be the variance and b be 4 times the mean times the skew (recalling that the skew approaches 0 in this case), i.e.
Substituting this into the original quadratic for optimal leverage under skew
We consider the plus and minus cases separately. After simplification, we have
From which we see that it is clear that it is the minus root that we should take if we want to ensure continuity with the case where we ignore skewness. A similar analysis can be done with kurtosis, but is more involved since we’d be dealing with a cubic instead of a quadratic (I personally cannot find the motivation to do it).
Empirical Testing
As of the date of writing the ETF Direxion Daily S&P500® Bull 3X Shares (SPXL) Performance has achieved a +10,084% return over the last 20 years, giving a CAGR of around 26.01%. Using the sample statistics of SPY returns, we plot the geometric growth rate against the leverage employed
Note that optimal leverage with the skew correction (2.58) is indeed lower than optimal leverage without the skew correction (3.05) and that CAGR after accounting for skew (~31%) is lower than CAGR without accounting for skew (~36%). Realized CAGR (~26%) is lower than both, possibly because of kurtosis, management fees, and the cost of leverage. In any case, the results above accord with our intuition that accounting for negative skewness should decrease the optimal leverage as well as the expected growth rate of wealth.
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Thanks for the post, though the first section seems to have swapped the definition of a and b (compared to the linked wiki page) -- the formula here requires decreasing the leverage for very large a, which does not make sense if a is profit.
You mention that if we only consider the constant and linear term of the Taylor expansion, we get f = mu/mu_2, which is equivalent to the non-skew non-kurtosis approximation of Kelly (mu / sigma^2). Wouldn't mu / (mu_2 - mu^2) be equivalent to non-skew Kelly? mu_2 is just E[X^2].