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Matthew's avatar

Thanks for the post, though the first section seems to have swapped the definition of a and b (compared to the linked wiki page) -- the formula here requires decreasing the leverage for very large a, which does not make sense if a is profit.

Yang's avatar

You mention that if we only consider the constant and linear term of the Taylor expansion, we get f = mu/mu_2, which is equivalent to the non-skew non-kurtosis approximation of Kelly (mu / sigma^2). Wouldn't mu / (mu_2 - mu^2) be equivalent to non-skew Kelly? mu_2 is just E[X^2].

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